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Question :

What was the number of schools having only facilities F1 and F4?

Started 3 weeks ago by Shashank in

Answer : 20

Explanatory Answer

 

Assume only F1 & F2 = A

 

We know from condition 8 that F1 and F2 have 162 students

 

A + x + 40 + x = 162

 

F2 = 313 = 162 + 26 + 45 + 30 + x

 

x = 50 and A = 22 

 

 

Now F1 & F4 have the same number of schools

 

We Calculate the values not common to both to balance the figures

 

F4 = 50 + 45 + 24 + 20 = 139

 

F1 = 50 + 25 + 22 + x = 139

 

x = 42

 

Now to calculate only F1 and F4

 

520 – 313 – 26 – 24 – 20 – 25 – 42 – 50 = 20

 

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