What is the percentage of votes polled in total by all the candidates who lost their security deposits while contesting for constituency A?
Started 2 weeks ago by Shashank in
Explanatory Answer
We know that candidates who failed to secure more 1/6 th of total valid votes lose their
security deposit.
Let us put the information we have in a table:
• From (1), we know that the 2 nd runner-up in A polled 95000-10000 = 85000 votes
• From (2), we know that everyone in C secured more than (1/ 6)* 600030 = 100005 votes . Also,
the minimum difference between any 2 candidates’ votes was 10,000.
• From (3), let’s assume the total no. of votes polled in D was 100x. Then votes polled by winner =
37,500 + 5x.
Also, we know that candidates who lost their deposit in D together polled 35% votes .
Total votes polled in A = 5,00,000
Total votes polled by top 3 candidates = 2,75,000 + 95,000 + 85,000 = 4,55,000
Votes polled by bottom 7 candidates = 5,00,000 – 4,55,000 = 45,000
We can see that 45,000 is clearly less than 1/6 th of 5,00,000 (83,333) . Hence, all the bottom 7
candidates lost their deposit.
Total % votes polled by them = \(({45000 \over {500000}})*100\) = 9%
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