Let us look at this one at a time. Statement 1 does not give us clear comparables, let us start with
statement 2.

Ratings in F and P are identical, so we can infer that Weightage for R > Weightage for I. 
R > I. 

Now, let us move to statement 3.

Ratings in F and R are identical, so we can infer that Weightage for I > Weightage for P. 
I > P. 
Now, let us combine these two inferences – we get R > I > P.

Now, let us look at Statement 1. 
Scores in P are identical. Best Ed has gotten better scores in F and R and a worse score in I. 
Further Best Ed has gotten better score by one grade in F and R, but worse score by two grades
in I. 
So, Best Ed’s better score in two grades is more than offset by High Q’s better score in one
parameter. 

High Q is -1 in F and R, but +2 in I. We know that weightage given for R > I. 
So, the -1 in R has a great impact, so the -1 in F should have much lower impact. 
In other words, weightage for F should be small and that for I should be high. 

Let us account for R > I > P first. 
Of the 4 possibilities, we can easily eliminate the last one as F cannot be 0.4. 
F cannot be 0.3 either, so the 3rd one can also be eliminated.

Even if F were 0.2, High Q would not be higher than Best End – the two scores would be equal. 
So, the weightages have to be F = 0.1, R = 0.4, P = 0.2 and I = 0.3. 
So, the weightages are as follows.

From the above table, we can see that the number of colleges which have overall scores between
31 and 40 both inclusive is 0.