Pipes A and C are fill pipes while Pipe B is a drain pipe of a tank. Pipe B empties the full tank in one hour less than the time taken by Pipe A to fill the empty tank. When pipes A, B and C are turned on together, the empty tank is filled in two hours. If pipes B and C are turned on together when the tank is empty and Pipe B is turned off after one hour, then Pipe C takes another one hour and 15 minutes to fill the remaining tank. If Pipe A can fill the empty tank in less than five hours, then the time taken, in minutes, by Pipe C to fill the empty tank is
Started 3 weeks ago by Shashank in
Explanatory Answer
Let the time taken by A to fill the tank alone be x hr, which implies the time taken by B to empty the tank alone is (x-1)hr B is the drainage pipe, and the time taken by C to fill the tank is y hours
It is given that when pipe A,B and C are turned on together, the empty tank is filled in two hours. Hence, 1/x- 1/x-1 +1/y= 1/2
It is given that if pipes B and C are turned on together when the tank is empty and pipe B is turned off after one hour, then pipe C takes another one hour and 15 min to fill the remaining tank
Hence, B worked for 1hr, and C worked for 2hr 15min, which is equal to 9/4hours
In 1 hour, B worked -1/x-1 units, and in 9/4 hours, C worked 9/4y units. Hence, 9/4y-1/x-1=1
Solving both the equations we get y=3/2 and x=3. Hence, the time taken by C is 3/2 hr which is equal to 90 Min
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