Question 1651 : What was the temperature outside, in degree Celsius, at 9 pm?
Video Explanation
Explanatory Answer
Following data was captured from the question:
| TIME | TEMPERATURE | AC - ON/OFF | MODE | OUTSIDE TEMP |
|---|---|---|---|---|
| 23:00 | 38 | ON | ||
| 23:30 | 32 | ON | ||
| 00:00 | 26 | OFF | ||
| 00:30 | 31 | ON | ||
| 01:00 | 26 | OFF | ||
| 01:30 | 30 | ON | ||
| 02:00 | 28 |
Since AC is turned OFF at 12:00, it must reach the outside temperature at 12:00 in 1 hour. It rises from 26 degrees to 31 degrees at 12:30 AM (an increase of 5 degrees in 30 minutes). It clearly states that the outside temperature will be 31 + 5 = 36 degree Celsius at 12:00 AM.
Similarly, AC is turned OFF at 1:00 AM, it must reach the outside temperature at 1:00 AM in 1 hour. It rises from 26 degrees to 30 degrees at 1:30 AM (an increase of 4 degrees in 30 minutes). It clearly states that the outside temperature will be 30 + 4 = 34 degree Celsius at 1:00 AM.
Also, temperature outside has been falling at a constant rate from 7 PM onward until 3 AM on a particular night.
| TIME | TEMPERATURE | AC - ON/OFF | MODE | OUTSIDE TEMP |
|---|---|---|---|---|
| 23:00 | 38 | ON | 38 | |
| 23:30 | 32 | ON | 37 | |
| 00:00 | 26 | OFF | NA | 36 |
| 00:30 | 31 | ON | 35 | |
| 01:00 | 26 | OFF | NA | 34 |
| 01:30 | 30 | ON | 33 | |
| 02:00 | 28 | 32 |
The question is "What was the temperature outside, in degree Celsius, at 9 pm?"
Solution: From the table we can infer that the outside temperature drops 1 degree Celsius for every 30 minutes. Temperature at 23:00 is 38 degrees. Hence at 9 PM it will be 38+1+1+1+1= 42 degrees Celsius.