Question 1669 : 

The number of distinct integer solutions (x,y) of the equation |x+y|+|xy|=2, is


Video Explanation


Explanatory Answer

We are thinking about two scenarios where xy and xy. When xy,

x+y+xy=22x=2x=1

So, the possibilities are ( 1,1 ), ( 1,0 ) and ( 1,1 )
When x=0,
The possibilities are (0,1) and (0,1)
When x=1
The possibilities are ( 1,1 ), ( 1,0 ) and ( 1,1 )
So, the number of distinct integer solutions =8

 


The question is "The number of distinct integer solutions (x,y) of the equation |x+y|+|xy|=2, is"

Hence, the answer is '8'

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The answer is

Choice 8 is the correct answer.