Question 1562 : 

How many buyers gave ratings on Day 1?


Video Explanation


Explanatory Answer

Day 2

Ratings Number of Buyers
1 5
2 10
3 5
4 20
5 10

Total number of Buyers in Day 2 = 50.

Daily Average on Day 2 =
(1×5 + 2×10 + 3×5 + 4×20 + 5×10) / 50 = 170 / 50 = 3.4

DAY 1:

Cumulative averages on Day 1 and Day 2 were 3 and 3.1 respectively.

Let the number of Buyers in Day 1 = x.

(3x + 170) / (x + 50) = 3.1

Solving, 3x + 170 = 3.1(x + 50);
3x + 170 = 3.1x + 155;
0.1x = 15;
x = 150.

Therefore, the number of Buyers in Day 1 = 150.

DAY 3:

Total number of Buyers in Day 3 = 100.

The numbers of buyers giving each product rating are non-zero multiples of 10.
Number of buyers giving rating 1 = Number of buyers giving rating 2 = Half of number of buyers giving rating 3.
The modes of the product ratings were 4 and 5.

DAY 3
Ratings Number of Buyers
1 A
2 A
3 2A
4 B (Mode)
5 B (Mode)

Sum of the number of buyers = 4A + 2B = 100.

The only possible solution for the equation and B value being the mode is A = 10 and B = 30.

DAY 3
Ratings Number of Buyers
1 10
2 10
3 20
4 30
5 30

Product rating on Day 3 = (1×10 + 2×10 + 3×20 + 4×30 + 5×30) / 100 = 360 / 100 = 3.6

Cumulative rating on Day 3 = (3×150 + 3.4×50 + 3.6×100) / (150 + 50 + 100) = 980 / 300 = 3.266

DAY NUMBER OF PASSENGERS DAILY AVERAGE CUMULATIVE AVERAGE
1 150 3 3
2 50 3.4 3.1
3 100 3.6 3.266

The question is "<p>How many buyers gave ratings on Day 1?</p>"

The answer is

Choice 150 is the correct answer.