There are four bottles. It is known that either one or two of these bottles contain(s) only P, while the remaining ones contain 85% P and 15% I. What is the minimum number of tests required to ascertain the exact number of bottles containing only P?
Started 6 days ago by Shashank in
Explanatory Answer
Answer- 1
We will take the weighted average approach here
Case 1 – 1 Bottle has 100% P and 3 bottles have 85% P
Weighted average = (1*100 + 3*85)/4 = 88.75%
Impurity will be detected
Case 2 - 2 Bottles has 100% P and 2 bottles have 85% P
Weighted average = (2*100 + 2*85)/4 = 92.5%
Impurity will not be detected
We can see that only 1 test will be enough to determine the total number of bottles with 100%
purity.
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