If the total score of Bimal is a multiple of 3, what is the score of Akhil on Day 2?
Started 1 month ago by Shashank in
Explanatory Answer
Step 1:
Let total score of Day 1, Day 2, Day 3, Day 4 and Day 5 be D1, D2, D3, D4 and D5 respectively.
Then, D1 + D2 = 30
D2 + D3 = 31
D3 + D4 = 32
D4 + D5 = 34
As per condition 2, D3 = D4 = 16
Therefore, D1 = 15, D2 = 15, D3 = 16, D4 = 16 and D5 = 18.
As per condition 1 and 3,
So, 2a + c = 16, where c > a. Therefore, possible combinations are (4, 8), (5, 6) but since all scores
of Chatur were multiples of 3, hence, (a, c) = (5, 6). This also implies Chatur’s unique highest score in the competition on Day 2 must be 9 and b = 3.
Step 2:
Here 9 > x > y and q > 6 > p
and x + y = 6 and p + q = 12
Possible combinations of (x, y) = (15, 1), (4, 2)
Possible combinations of (p, q) = (5, 7), (4, 8)
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