Started 8 months ago by Shashank in
Explanatory Answer
Let’s assume (x + (1/x)) = A
A – 3A + 2 = 0
A = 2,1
(x + (1/x)) = 2
X = 1,
(x + (1/x)) = 1 à This case is not possible as (x + (1/x)) >= 2 if x is positive and (x + (1/x)) <= -2 if
x is negative.
Therefore, we have 1 distinct real root.
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