An alloy is prepared by mixing three metals A, B and C in the proportion 3:4:7 by volume. Weights&nbsp;of the same volume of the metals A, B and C are in the ratio 5:2:6. In 130 kg of the alloy, the&nbsp;weight, in kg, of the metal C is:

CAT 2020 Question Paper | CAT Verbal Ability Slot 1

Question :

An alloy is prepared by mixing three metals A, B and C in the proportion 3:4:7 by volume. Weights of the same volume of the metals A, B and C are in the ratio 5:2:6. In 130 kg of the alloy, the weight, in kg, of the metal C is:

Started 3 months ago by Shashank in

0 62

A.
48
B.
96
C.
84
D.
70

Option C is the correct answer.

Explanatory Answer

We have been given the ratio of the volume and weights of the volume (1-unit cube of A will
have a weight of 5x).
Hence to find the actual weights we must multiply the volume and weights of volume.
A : B : C = (3*5 : 4*2 : 7*6) = 15 : 8 : 42
Total weight = 15x + 8x + 42x = 65x = 130
x = 2
Therefore weight of C = 42*2 = 84 Kgs