John takes twice as much time as Jack to finish a job. Jack and Jim together take one-thirds of the time to finish the job than John takes working alone. Moreover, in order to finish the job, John takes three days more than that taken by three of them working together. In how many days will Jim finish the job working alone?
Started 4 days ago by Shashank in
Explanatory Answer
Let’s assume the amount of work done by each person in a day:
John – x
Jack – 2x
If Jack and Jim together take 1/3 of the time that John takes, it means they together complete 3 times the work that John alone completes in a day.
Hence, Jack + Jim = 3x
Jim – x
Assuming the work to be done is 100 units.
Number of days taken by each person is:
John – 100/x
Jack – 50/x
Jim – 100/x
All 3 together – 25/x
Therefore, 100/x = 25/x + 3
100 = 25 + 3x
3x = 75
x = 25
Jim will finish the job alone in 100/x = 100/25 = 4 days
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