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Question :
Aron bought some pencils and sharpeners. Spending the same amount of money as Aron, Aditya bought twice as many pencils and 10 less sharpeners. If the cost of one sharpener is 2 more than the cost of a pencil, then the minimum possible number of pencils bought by Aron and Aditya together is
Started 1 month ago by Shashank in
Option A
is the correct answer.
Explanatory Answer
Let cost of pencil be ‘x’ and sharpener be ‘x+2’.
Amount spent by Aron = p*x + s*(x+2)
Amount spent by Aditya = 2p*x + (s- 10)( x+2)
Therefore: px + sx + 2s = 2px + sx - 10x + 2s – 20
px - 10x - 20 = 0
x(p-10) = 20
Since p-10 > 0, p(min) = 11
Total pencils = p + 2p = 33
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