If (a + b√n) is the positive square root of (29 − 12√5),
where a and b are integers, and n is a natural number,
Then, find the maximum possible value of (a + b + n).
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Explanatory Answer
Given: √(29 − 12√5) = a + b√n
Step 1: Square both sides
(a + b√n)^2 = 29 − 12√5
a^2 + n b^2 + 2ab√n = 29 − 12√5
Step 2: Equate rational and irrational parts
Rational part: a^2 + n b^2 = 29
Irrational part: 2ab√n = −12√5
=> ab√n = −6√5
=> n = 5, ab = −6
Step 3: Solve a^2 + 5b^2 = 29 with ab = −6
Possible values: (a = 3, b = −2) or (a = −3, b = 2)
Step 4: Identify positive and negative roots
Positive root: −3 + 2√5
Negative root: 3 − 2√5
Step 5: To maximize a + b + n, modify the expression:
Take a = −3, b = 1, n = 20
Step 6: Compute maximum possible value
a + b + n = −3 + 1 + 20 = 18
Answer: Maximum possible value of (a + b + n) = 18
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