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Question :

A certain amount of water was poured into a 300 litre container and the remaining portion of the container
was filled with milk. Then an amount of this solution was taken out from the container which was twice the
volume of water that was earlier poured into it, and water was poured to refill the container again. If the
resulting solution contains 72% milk, then the amount of water, in litres, that was initially poured into the
container was

Started 4 hours ago by Admin in

Answer : 30

Explanatory Answer

Initial quantity of water in the container =x
So, initial quantity of milk in the container =300x
Part of mixture taken out =2x300
Part of mixture that is retained =12x300
So, part of milk that is retained =(300x)(12x300)
Also, quantity of milk that is retained after the iteration =72% of 300=216
Then,

(300x)(12x300)=21690000300x600x+2x2=216×3002x2900x+25200=0x2450x+12600=0(x420)(x30)=0x=420 (or) x=30

The total content itself 300 litre. So, x=420 is inadmissible.
Thus, amount of water that was initially poured = 30 litre

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