The number of distinct integer solutions (x,y) of the equation |x+y|+|x−y|=2, is
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Explanatory Answer
We are thinking about two scenarios where x≥y and x≥−y. When x≥y,
So, the possibilities are ( 1,1 ), ( 1,0 ) and ( 1,−1 )
When x=0,
The possibilities are (0,1) and (0,−1)
When x=−1
The possibilities are ( −1,1 ), ( −1,0 ) and ( −1,−1 )
So, the number of distinct integer solutions =8
The question is "The number of distinct integer solutions (x,y) of the equation |x+y|+|x−y|=2, is"
Hence, the answer is '8'
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