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Question :

For any non-zero real number x, let f(x)+2f(1/x)=3x. Then, the sum of all possible values of x for which f(x)=3, is

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Option B is the correct answer.

Explanatory Answer

 

f(x)+2f(1x)=3x

Put x=1/x,

f(1x)+2f(x)=3x

Solving (1) & (2),
(1) 

(1)2×(2)f(x)+2f(1x)=3x2f(1x)+4f(x)=6x

Subtracting, we get

3f(x)=6x3x

So,

f(x)=2xx

Now,

f(x)=3 implies, 2xx=3x2+3x2=0

Sum of the roots =b/a
Answer =3

 


The question is "For any non-zero real number x, let f(x)+2f(1x)=3x. Then, the sum of all possible values of x for which f(x)=3, is"

Hence, the answer is '-3'
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