Two ships meet mid-ocean, and then, one ship goes south and the other ship goes west, both travelling at constant speeds. Two hours later, they are 60 km apart. If the speed of one of the ships is 6 km per hour more than the other one, then the speed, in km per hour, of the slower ship is
Started 1 week ago by Shashank in
Explanatory Answer
Let the speeds of the boats be x kmph and x + 6 kmph.
After 2 hours, the distance travelled by the boats is 2x km and 2x + 12 kms respectively.
The distance between them is 60 kms.
602 = (2x)2 + (2x + 12)2
3600 = 4 x2 + 4 x2 + 144 + 48x
900 = 2 x2 + 36 + 12 x
450 = x2 + 18 + 6 x
x2 + 6x - 432 = 0
x2 + 24x - 18x - 432 = 0
x = 18 or x = -24
The speed of the slower boat is 18 kmph.
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