Let x1 be least number and x10 be largest numberaccording to question→X2 + X3+ X4 + X5 + X6 + X7 + X8 + X9 + X10 = 47 x 9 = 423 ----(1)Similarly,⇒ x1 + x2 +X3 + X4 + X5 + X6 + X7 + X8 + X9 = 42 x 9 = 378 ----(2)Subtract equation 2 from 1X10-X1 = 423 - 378 = 45Sum of 10 observation from equation 1 = 423 + x1⇒ Now minimum value of x10 will be 47 and minimum value of x1 will be 2. hence minimum average = 425/10 = 42.5⇒ maximumm value of x1 is 42 hence maximum average will be 465/10 = 46.5⇒ Difference of average = 46.5 - 42.5 = 4The maximum possible mean exceeds the minimum possible mean by 4

Your browser does not support the audio element.

can you please explain the solution in a group of 10 students , the mean of lowest 9 scores is 42 and mean of highest 9 scores is 47. for the entire group of 10 students. the maximum possible mean exceeds the minimum possible mean by?

can you please explain the solution in a group of 10 students , the mean of lowest 9 scores is 42 and mean of highest 9 scores is 47. for the entire group of 10 students. the maximum possible mean exceeds the minimum possible mean by?