WhatsApp Image 2024-08-10 at 09.18.08_bfee379d.jpg 133.58 KBUnderstanding the ProblemWe have a rectangle ABCD with a semicircle removed, whose diameter is the side AB of the rectangle. We know the area of the rectangle and the semicircle. We need to find the perimeter of the remaining shape.Visualizing the ProblemSolution Steps * Find the length of AB:   * Area of the semicircle = 72π sq cm   * Area of a full circle = 2 * Area of a semicircle = 144π sq cm   * Radius of the circle (or half of AB) = √(Area of circle / π) = √(144π / π) = 12 cm   * Length of AB (diameter) = 2 * radius = 24 cm * Find the length of BC:   * Area of the rectangle = 768 sq cm   * Length of BC = Area / AB = 768 / 24 = 32 cm * Calculate the perimeter of the leftover portion:   * Perimeter = (Length of BC + CD + DA) + (Circumference of the semicircle)   * Circumference of the semicircle = π * radius = 12π cm   * Perimeter = (32 + 24 + 32) + 12π = 88 + 12π cmFinal AnswerThe perimeter of the leftover portion is 88 + 12π cm.Therefore, the correct answer is D.

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Thanks a lot

Thanks a lot

how to approach??? which part to be solved 1st ?? image.png 29.02 KB

how to approach??? which part to be solved 1st ?? image.png 29.02 KB