Started 3 weeks ago by Abhiraj Subhedar in
For any natural number n, suppose the sum of the first n terms of an arithmetic progression is (n + 2n?). If the nth term of the progression is divisible by 9, then the smallest possible value of nis
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3 Replies
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@aaditya-cat-995-percentile2037
Replied 4 months ago
CK Doubt 12856.mp4 5.9 MB
@abhirajsu913
Replied 2 weeks ago
how to solve in easy way? For any natural number n, suppose the sum of the first n terms of an arithmetic progression is (n + 2n?). If the nth term of the progression is divisible by 9, then the smallest possible value of nis
@abhirajsu913
Replied 2 weeks ago
how to solve in easy way? For any natural number n, suppose the sum of the first n terms of an arithmetic progression is (n + 2n?). If the nth term of the progression is divisible by 9, then the smallest possible value of nis