The correct ans is 4:3:6:2

So ,did i get my answer in a wrong method( by fluke) or was my method was correct ?

So ,did i get my answer in a wrong method( by fluke) or was my method was correct ?

Your method is correct

I want to know where I went wrong in my solution Question ) How must a shop owner mix 4 types of sugar worth Rs.95, Rs.60, Rs.90 and Rs.50 per kg so that he can make the mixture of these sugar worth Rs.80 per kg?  | a) 3:2:4:8 |  | b) 3:2:4:6 |  | с) 6:2:4:5 |  | d) 3:2:5:9  |  | e) None of these IMG_1749.jpeg 475.53 KBMy answer is a:b:c:d = 4:3:6:2The answer in the solutions is a:b:c:d = 3:2:4:6 Please let me know another way to solve this peculiar solution or let me know where I went wrong in my approach where I equated all 3 set of ratios in a single ratio.

I want to know where I went wrong in my solution Question ) How must a shop owner mix 4 types of sugar worth Rs.95, Rs.60, Rs.90 and Rs.50 per kg so that he can make the mixture of these sugar worth Rs.80 per kg?  | a) 3:2:4:8 |  | b) 3:2:4:6 |  | с) 6:2:4:5 |  | d) 3:2:5:9  |  | e) None of these IMG_1749.jpeg 475.53 KBMy answer is a:b:c:d = 4:3:6:2The answer in the solutions is a:b:c:d = 3:2:4:6 Please let me know another way to solve this peculiar solution or let me know where I went wrong in my approach where I equated all 3 set of ratios in a single ratio.