Let x and y be positive real numbers such that log5(x + y) + log5(x - y) = 3, and log2y - log2x = 1

Let x and y be positive real numbers such that log₅(x + y) + log₅(x - y) = 3, and log₂y - log₂x = 1 - log₂3. Then xy equals

Started 8 months ago by Shashank in

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