Hi Aaditya.(6x^2 + 7x + 12) / (5x^2 + 4x + 30) < 1-> (6x^2 + 7x + 12) < (5x^2 + 4x + 30)              (since the quadratic in the denominator is positive for all the real values of x)-> x^2 + 3x - 18 < 0-> (x + 6) * (x - 3) < 0-> -6 < x < 3Now, the largest integral value of x is 2.

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pls reply fast For the expression to hold true , the integer value of x cannot be more than ___.

pls reply fast For the expression to hold true , the integer value of x cannot be more than ___.