Started 3 weeks ago by Shubham Kumar Singh in
From the top of a hill of 90 m height, the angles of depressions of the top and foot of a tower are observed as 15o and 60o respectively. Find the height of the tower. (in m) (Given: tan15o = 0.26)30( √3 -1)60(3- √3)90( √3 -1)30(√3- 3)
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3 Replies
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@monika-cat-999-percentile2863
Replied 10 months ago
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@shubhamku445
Replied 3 weeks ago
solve question. its answer options are confusing and i am not getting the same From the top of a hill of 90 m height, the angles of depressions of the top and foot of a tower are observed as 15o and 60o respectively. Find the height of the tower. (in m) (Given: tan15o = 0.26)30( √3 -1)60(3- √3)90( √3 -1)30(√3- 3)
@shubhamku445
Replied 3 weeks ago
solve question. its answer options are confusing and i am not getting the same From the top of a hill of 90 m height, the angles of depressions of the top and foot of a tower are observed as 15o and 60o respectively. Find the height of the tower. (in m) (Given: tan15o = 0.26)30( √3 -1)60(3- √3)90( √3 -1)30(√3- 3)