Started 3 weeks ago by Bhavya Aggarwal in
5 Consecutive alphabet from English alphabet are selected at random. Find out the probability that two of them are vowel.Explanation: First case is a, b, c, d and eSecond case is e, f, g, h and IThese are the only two possible casesRequired probability = 2/21why are not we going by pnc in this method and considering all the vowels 5c2
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3 Replies
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@catking-doubt-solving-team1054
Replied 9 months ago
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@bhavyaag408
Replied 3 weeks ago
Unable to understand the answer of this question 5 Consecutive alphabet from English alphabet are selected at random. Find out the probability that two of them are vowel.Explanation: First case is a, b, c, d and eSecond case is e, f, g, h and IThese are the only two possible casesRequired probability = 2/21why are not we going by pnc in this method and considering all the vowels 5c2
@bhavyaag408
Replied 3 weeks ago
Unable to understand the answer of this question 5 Consecutive alphabet from English alphabet are selected at random. Find out the probability that two of them are vowel.Explanation: First case is a, b, c, d and eSecond case is e, f, g, h and IThese are the only two possible casesRequired probability = 2/21why are not we going by pnc in this method and considering all the vowels 5c2