Priya can reach S from T via R or V. In the east-west direction, the first train from P arrives at T at time = 6 am + ( 4 × 2 ) + ( 3 × 1 ) = 11 (4×2)+(3×1)= 11 minutes = 6:11 am 

Since T is at time = 6 am + ( 4 × 2 ) + ( 3 × 1 ) = 11 (4×2)+(3×1)= 11 minutes = 6:11 am 

Since T is a junction so this train will halt for 2 minutes at T and leave at 6:13. 

Since every 10 minutes, a train starts from P in the east-west direction so the latest by which Priya will be able to board such a train is at 10:33 am. In the north-south direction, the first train from B arrives at T at time = 6:11 am Since T is a junction so this train will halt for 2 minutes at T and leave at 6:13. Since every 15 minutes a train starts from P in the east-west direction so the latest by which Priya will board a train for R from T at 10:28 am. 

There are 3 stations between T and R Travelling time between T and R = ( 4 × 3 ) + ( ( 3 × 1 ) ) =

15 (4×3)+((3×1))= 15 minutes 

Therefore, Priya will board a train for R from T at 10:28 am. There are 3 stations between T and R Travelling time between T and R = ( 4 × 3 ) + ( ( 3 × 1 ) ) = 15 (4×3)+((3×1))= 15 minutes 

Therefore, Priya will reach R latest by 10:43 am In the east-west direction, the first train from M arrives at R at time = 6 am + ( 4 × 2 ) + ( 3 × 1 ) = 11 (4×2)+(3×1)= 11 minutes = 6:11 am 

Since V is a junction so this train will halt for 2 minutes at V and leave at 6:13. Since every 15 minutes, a train starts from M in the north-south direction, 

so the latest by which Priya will be able will be able to board such a train from V is at 11:03 am.

There are 3 stations between V and S Travelling time between R and S = ( 4 × 3 ) + ( ( 3 × 1 ) ) =

15 (4×3)+((3×1))= 15 minutes 

Time by which she reaches S = 11:03 +15 minutes = 11:18 am