How many of the students surveyed supported proposal B, did not support proposal A and preferred Ragini as student union president?
Started 1 month ago by Shashank in
Explanatory Answer
The set of students who like Sunita and Ragini are disjoint sets.
Hence, the Venn diagram can be drawn as follows
There are 500 students in all.
From statement (2)
Sunita = 200. Hence, Ragini = 300.
From statement (1) A (Sunita) + A (Ragini) = 250 and B (Sunita) + B (Ragini) = 250.
From (2), A (Sunita) = 160. Hence, A (Ragini) = 90.
From (4), B (Sunita) = 20 % of 250 = 50. Hence, B (Ragini) = 200.
From (6), g (Sunita) = 50 and hence, b (Sunita) = 0 and a (Sunita) = 110. Hence, n (Sunita) =
40.
From (7), n (Ragini) = 60
It is given that 250 support B, hence the other 250 do not support B.
From (5), (a + n) of Ragini = 40 % of 250 = 100. Hence, a (Ragini) = 40.
Thus, the final solution is as follows.
The students who supported proposal B but not A are b (Sunita) and b (Ragini). Among
them those supported Ragini are b (Ragini) 150. Ans: (150)
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