For a 4-digit number, the sum of its digits in the thousands, hundreds and tens places is 14, the sum of its digits in the hundreds, tens and units places is 15, and the tens place digit is 4 more than the units place digit. Then the highest possible 4-digit number satisfying the above conditions is
Started 3 months ago by Shashank in
Explanatory Answer
Let the number be abcd
a + b + c = 14 –(1)
b + c + d = 15 –(2)
c = d + 4 – (3)
Eq (2) – (1) =
d – a = 1
d = a+1 put in eq (3)
c = a + 1 + 4
c = a + 5 –(4)
Hence, ‘a’ can take max value of 4 when c = 9
Put value of c from (4) to (1)
b + 2a + 5 = 14
b = 1 (When a is max = 4)
From (3) ‘d’ can take maximum value of 5.
Hence answer is 4195
-
No one is replied to this question yet. Be first to reply!