Started 3 months ago by Shashank in
Explanatory Answer
Given that AM (x, y, z) = 80
So, x + y + z = 80 × 3 = 240 ----- (1)
Also, AM (x, y, z, u, v) = 75
So, x + y + z + u + v = 75 × 5 = 375 ----- (2)
Equation (2) – (1), we get
u + v = 375 - 240 = 135
Its also given that, u = \((x+y)\over2\) and v = \((z+y)\over2\)
So, u + v = \({(x+y+z)\over2} + {y\over2}\)
\({240\over2} + {y\over2} = 135 => y = 30\)
Substituting this value in (1), we get x + z = 210
It’s given that x ≥ z
x would take the minimum value when x = z
=> 2x = 210
=> x (min) = 105
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