CATKing Forum · CATKing Forum

01.

Which house in Block YY has parking space?

A.
F2
B.
F1
C.
E2
D.
E1

Option D is the correct answer.

Video Explanation

Explanatory Answer

02.

What is the maximum possible quoted price (in lakhs of Rs.) for a vacant house in Column-E?

Answer : 21

Video Explanation

Explanatory Answer

03.

Which of the following options best describes the number of vacant houses in Row-2?

A.
Either 3 or 4
B.
Either 2 or 3
C.
Exactly 3
D.
Exactly 2

Option B is the correct answer.

Video Explanation

Explanatory Answer

04.

Which of the following houses are definitely occupied?

A.
F2 and A2
B.
D2 and B2
C.
D2 and B1
D.
A1 and D2

Option C is the correct answer.

Video Explanation

Explanatory Answer

05.

How many houses are vacant in Block XX?

Answer : 3

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Explanatory Answer

06.

The schematic diagram below shows 12 rectangular houses in a housing complex. House numbers are mentioned in the rectangles representing the houses. The houses are located in six columns – Column-A through Column-F, and two rows – Row-1 and Row-2. The houses are divided into two blocks - Block XX and Block YY. The diagram also shows two roads, one passing in front of the houses in Row-2 and another between the two blocks.

Some of the houses are occupied. The remaining ones are vacant and are the only ones available for sale.

The road adjacency value of a house is the number of its sides adjacent to a road. For example, the road adjacency values of C2, F2, and B1 are 2, 1, and 0, respectively. The neighbour count of a house is the number of sides of that house adjacent to occupied houses in the same block. For example, E1 and C1 can have the maximum possible neighbour counts of 3 and 2, respectively.

The base price of a vacant house is Rs. 10 lakhs if the house does not have a parking space, and Rs. 12 lakhs if it does. The quoted price (in lakhs of Rs.) of a vacant house is calculated as (base price) + 5 × (road adjacency value) + 3 × (neighbour count).

The following information is also known.
1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.

2. Row-1 has two occupied houses, one in each block.

3. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.

4. There is only one house with parking space in Block YY.

01.

How many houses are vacant in Block XX?

Answer : 3

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Explanatory Answer

02.

Which of the following houses are definitely occupied?

A.
F2 and A2
B.
D2 and B2
C.
D2 and B1
D.
A1 and D2

Option C is the correct answer.

Video Explanation

Explanatory Answer

03.

Which of the following options best describes the number of vacant houses in Row-2?

A.
Either 3 or 4
B.
Either 2 or 3
C.
Exactly 3
D.
Exactly 2

Option B is the correct answer.

Video Explanation

Explanatory Answer

04.

What is the maximum possible quoted price (in lakhs of Rs.) for a vacant house in Column-E?

Answer : 21

Video Explanation

Explanatory Answer

05.

Which house in Block YY has parking space?

A.
F2
B.
F1
C.
E2
D.
E1

Option D is the correct answer.

Video Explanation

Explanatory Answer

07.

Which pair of performances were composed by the same composer?

A.
The third and the seventh
B.
The first and the seventh
C.
The first and the sixth
D.
The second and the sixth

Option C is the correct answer.

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Explanatory Answer

08.

The sixth performance was composed by:

A.
Gagan
B.
Ashman
C.
Badal
D.
Dyu

Option C is the correct answer.

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Explanatory Answer

09.

Which of the following is FALSE?

A.
Queen did not perform in any item composed by Gagan.
B.
Rani did not perform in any item composed by Badal.
C.
Samragni did not perform in any item composed by Ashman.
D.
Princess did not perform in any item composed by Dyu.

Option A is the correct answer.

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Explanatory Answer

10.

Which of the following is true?

A.
The third performance was composed by Ashman.
B.
The second performance was composed by Dyu.
C.
The second performance was composed by Gagan.
D.
The third performance was composed by Dyu.

Option B is the correct answer.

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Explanatory Answer

11.

Princess, Queen, Rani and Samragni were the four finalists in a dance competition. Ashman, Badal, Gagan and Dyu were the four music composers who individually assigned items to the dancers. Each dancer had to individually perform in two dance items assigned by the different composers. The first items performed by the four dancers were all assigned by different music composers. No dancer performed her second item before the performance of the first item by any other dancers. The dancers performed their second items in the same sequence of their performance of their first items.

The following additional facts are known.

i) No composer who assigned item to Princess, assigned any item to Queen.
ii) No composer who assigned item to Rani, assigned any item to Samragni.
iii) The first performance was by Princess; this item was assigned by Badal.
iv) The last performance was by Rani; this item was assigned by Gagan.
v) The items assigned by Ashman were performed consecutively. The number of performances between items assigned by each of the remaining composers was the same.

01.

Which of the following is true?

A.
The third performance was composed by Ashman.
B.
The second performance was composed by Dyu.
C.
The second performance was composed by Gagan.
D.
The third performance was composed by Dyu.

Option B is the correct answer.

Video Explanation

Explanatory Answer

02.

Which of the following is FALSE?

A.
Queen did not perform in any item composed by Gagan.
B.
Rani did not perform in any item composed by Badal.
C.
Samragni did not perform in any item composed by Ashman.
D.
Princess did not perform in any item composed by Dyu.

Option A is the correct answer.

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Explanatory Answer

03.

The sixth performance was composed by:

A.
Gagan
B.
Ashman
C.
Badal
D.
Dyu

Option C is the correct answer.

Video Explanation

Explanatory Answer

04.

Which pair of performances were composed by the same composer?

A.
The third and the seventh
B.
The first and the seventh
C.
The first and the sixth
D.
The second and the sixth

Option C is the correct answer.

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12.

Which among the digits 4, 6, 7 and 8 cannot be represented by the letter G?

Answer : 6

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13.

Which among the digits 3, 4, 6 and 7 cannot be represented by the letter D?

Answer : 7

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14.

Which digit does the letter B represent?

Answer : 9

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15.

Which digit does the letter A represent?

Answer : 1

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16.

01.

Which digit does the letter A represent?

Answer : 1

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02.

Which digit does the letter B represent?

Answer : 9

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03.

Which among the digits 3, 4, 6 and 7 cannot be represented by the letter D?

Answer : 7

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04.

Which among the digits 4, 6, 7 and 8 cannot be represented by the letter G?

Answer : 6

Video Explanation

Explanatory Answer

17.

What was Tanzi's score in Round 3?

A.
1
B.
5
C.
3
D.
4

Option A is the correct answer.

Video Explanation

Explanatory Answer

18.

Which of the following statements is true?

A.
Zeneca’s score was 23.
B.
Zeneca was the highest scorer
C.
Xyla was the highest scorer.
D.
Xyla’s score was 23

Option C is the correct answer.

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Explanatory Answer

19.

What was Zeneca's total score?

A.
21
B.
22
C.
23
D.
24

Option D is the correct answer.

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Explanatory Answer

20.

What was the highest total score?

A.
23
B.
24
C.
25
D.
21

Option C is the correct answer.

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Explanatory Answer

21.

01.

What was the highest total score?

A.
23
B.
24
C.
25
D.
21

Option C is the correct answer.

Video Explanation

Explanatory Answer

02.

What was Zeneca's total score?

A.
21
B.
22
C.
23
D.
24

Option D is the correct answer.

Video Explanation

Explanatory Answer

03.

Which of the following statements is true?

A.
Zeneca’s score was 23.
B.
Zeneca was the highest scorer
C.
Xyla was the highest scorer.
D.
Xyla’s score was 23

Option C is the correct answer.

Video Explanation

Explanatory Answer

04.

What was Tanzi's score in Round 3?

A.
1
B.
5
C.
3
D.
4

Option A is the correct answer.

Video Explanation

Explanatory Answer

22.

Which of the following statements is necessarily true?

A.
There are two empty shelves between the biscuits and the candies.
B.
All candies are kept before biscuits.
C.
All biscuits are kept before candies
D.
There are at least four shelves between items B and C.

Option D is the correct answer.

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Explanatory Answer

23.

Which of the following can represent the numbers of the empty shelves in a possible arrangement?

A.
1,7,11,12
B.
1,5,6,12
C.
1,2,6,12
D.
1,2,8,12

Option C is the correct answer.

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Explanatory Answer

24.

Which of the following items is not a type of biscuit?

A.
B
B.
A
C.
L
D.
G

Option D is the correct answer.

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Explanatory Answer

25.

In how many different ways can the items be arranged on the shelves?

A.
2
B.
1
C.
4
D.
8

Option D is the correct answer.

Video Explanation

Explanatory Answer

26.

A supermarket has to place 12 items (coded A to L) in shelves numbered 1 to 16. Five of these items are types of biscuits, three are types of candies and the rest are types of savouries. Only one item can be kept in a shelf. Items are to be placed such that all items of same type are clustered together with no empty shelf between items of the same type and at least one empty shelf between two different types of items. At most two empty shelves can have consecutive numbers.

The following additional facts are known.
1. A and B are to be placed in consecutively numbered shelves in increasing order.
2. I and J are to be placed in consecutively numbered shelves both higher numbered than the shelves in which A and B are kept.
3. D, E and F are savouries and are to be placed in consecutively numbered shelves in increasing order after all the biscuits and candies.
4. K is to be placed in shelf number 16.
5. L and J are items of the same type, while H is an item of a different type.
6. C is a candy and is to be placed in a shelf preceded by two empty shelves.
7. L is to be placed in a shelf preceded by exactly one empty shelf.

01.

In how many different ways can the items be arranged on the shelves?

A.
2
B.
1
C.
4
D.
8

Option D is the correct answer.

Video Explanation

Explanatory Answer

02.

Which of the following items is not a type of biscuit?

A.
B
B.
A
C.
L
D.
G

Option D is the correct answer.

Video Explanation

Explanatory Answer

03.

Which of the following can represent the numbers of the empty shelves in a possible arrangement?

A.
1,7,11,12
B.
1,5,6,12
C.
1,2,6,12
D.
1,2,8,12

Option C is the correct answer.

Video Explanation

Explanatory Answer

04.

Which of the following statements is necessarily true?

A.
There are two empty shelves between the biscuits and the candies.
B.
All candies are kept before biscuits.
C.
All biscuits are kept before candies
D.
There are at least four shelves between items B and C.

Option D is the correct answer.

Video Explanation

Explanatory Answer

27.

List of all the vendors who are among the top three vendors on all six aspects is:

A.
None of the Vendors
B.
Vendor 1
C.
Vendor 1 and Vendor 3
D.
Vendor 3

Option D is the correct answer.

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Explanatory Answer

28.

List of all the vendors who are among the top two scorers on the maximum number of aspects is:

A.
Vendor 1 and Vendor 2
B.
Vendor 2, Vendor 3 and Vendor 4
C.
Vendor 2 and Vendor 5
D.
Vendor 1 and Vendor 5

Option D is the correct answer.

Video Explanation

Explanatory Answer

29.

A vendor's final score is the average of their scores on all six aspects. Which vendor has the highest final score?

A.
Vendor 1
B.
Vendor 3
C.
Vendor 4
D.
Vendor 2

Option B is the correct answer.

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Explanatory Answer

30.

On which aspect is the median score of the five vendors the least?

A.
Cost
B.
Quality
C.
Reliability
D.
Customer Service

Option D is the correct answer.

Video Explanation

Explanatory Answer

31.

Five vendors are being considered for a service. The evaluation committee evaluated each vendor on six aspects – Cost, Customer Service, Features, Quality, Reach, and Reliability. Each of these evaluations are on a scale of 0 (worst) to 100 (perfect). The evaluation scores on these aspects are shown in the radar chart. For example, Vendor 1 obtains a score of 52 on Reliability, Vendor 2 obtains a score of 45 on Features and Vendor 3 obtains a score of 90 on Cost

CAT DI LR 2019 Slot 1

01.

On which aspect is the median score of the five vendors the least?

A.
Cost
B.
Quality
C.
Reliability
D.
Customer Service

Option D is the correct answer.

Video Explanation

Explanatory Answer

02.

A vendor's final score is the average of their scores on all six aspects. Which vendor has the highest final score?

A.
Vendor 1
B.
Vendor 3
C.
Vendor 4
D.
Vendor 2

Option B is the correct answer.

Video Explanation

Explanatory Answer

03.

List of all the vendors who are among the top two scorers on the maximum number of aspects is:

A.
Vendor 1 and Vendor 2
B.
Vendor 2, Vendor 3 and Vendor 4
C.
Vendor 2 and Vendor 5
D.
Vendor 1 and Vendor 5

Option D is the correct answer.

Video Explanation

Explanatory Answer

04.

List of all the vendors who are among the top three vendors on all six aspects is:

A.
None of the Vendors
B.
Vendor 1
C.
Vendor 1 and Vendor 3
D.
Vendor 3

Option D is the correct answer.

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Explanatory Answer

32.

What is the sum of the ranks of Delhi in the three categories of crimes?

Answer : 5

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Explanatory Answer

33.

Which of the following is DEFINITELY true about the ranks of states/UT in the ‘other crimes’ category?
i) Tamil Nadu: 2
ii) Puducherry: 3

A.
only ii)
B.
both i) and ii)
C.
only i)
D.
neither i), nor ii)

Option B is the correct answer.

Video Explanation

Explanatory Answer

34.

01.

What is the rank of Kerala in the ‘IPC crimes’ category?

Answer : 5

Video Explanation

Explanatory Answer

02.

Which of the following is DEFINITELY true about the ranks of states/UT in the ‘other crimes’ category?
i) Tamil Nadu: 2
ii) Puducherry: 3

A.
only ii)
B.
both i) and ii)
C.
only i)
D.
neither i), nor ii)

Option B is the correct answer.

Video Explanation

Explanatory Answer

03.

In the two states where the highest total number of cases are registered, the ratio of the total number of cases in IPC crimes to the total number in SLL crimes is closest to Ans :

A.
19:20
B.
11:10
C.
1:9
D.
3:2

Option C is the correct answer.

Video Explanation

Explanatory Answer

04.

What is the sum of the ranks of Delhi in the three categories of crimes?

Answer : 5

Video Explanation

Explanatory Answer

35.

What is the rank of Kerala in the ‘IPC crimes’ category?

Answer : 5

Video Explanation

Explanatory Answer

36.

In the two states where the highest total number of cases are registered, the ratio of the total number of cases in IPC crimes to the total number in SLL crimes is closest to Ans :

A.
19:20
B.
11:10
C.
1:9
D.
3:2

Option C is the correct answer.

Video Explanation

Explanatory Answer

37.

Should a new person stand at intersection d, who among the six would she see?

A.
V and X only
B.
U and Z only
C.
U and W only
D.
W and X only

Option D is the correct answer.

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Explanatory Answer

38.

What is the minimum number of street segments that X must cross to reach Y?

A.
3
B.
2
C.
1
D.
4

Option B is the correct answer.

Video Explanation

Explanatory Answer

39.

Who can V see?

A.
U, W and Z only
B.
U and Z only
C.
Z only
D.
U only

Option B is the correct answer.

Video Explanation

Explanatory Answer

40.

Who is standing at intersection a?

A.
W
B.
Y
C.
No one
D.
V

Option C is the correct answer.

Video Explanation

Explanatory Answer

41.

01.

Who is standing at intersection a?

A.
W
B.
Y
C.
No one
D.
V

Option C is the correct answer.

Video Explanation

Explanatory Answer

02.

Who can V see?

A.
U, W and Z only
B.
U and Z only
C.
Z only
D.
U only

Option B is the correct answer.

Video Explanation

Explanatory Answer

03.

What is the minimum number of street segments that X must cross to reach Y?

A.
3
B.
2
C.
1
D.
4

Option B is the correct answer.

Video Explanation

Explanatory Answer

04.

Should a new person stand at intersection d, who among the six would she see?

A.
V and X only
B.
U and Z only
C.
U and W only
D.
W and X only

Option D is the correct answer.

Video Explanation

Explanatory Answer

42.

What was the buying exchange rate of currency C with respect to currency L on that day?

A.
1.10
B.
0.95
C.
2.20
D.
1.90

Option D is the correct answer.

Video Explanation

Explanatory Answer

In currency transactions, getting the basic outline is very important.
So, if the base rate of A w.r.t to L is 100, then to buy one unit of A, we need 95 units of L and if we
sell one unit of A, we will get 110 units of L.
Let us say the base rate of A w.r.t to L is 100k, then the base rate of B w.r.t to L is 120k and that of
C is 1k.
To buy one unit of A, we need 95k units of L; if we sell one unit of A, we will get 110k units of L.
To buy one unit of B, we need 114k units of L; if we sell one unit of B, we will get 132k units of L.
To buy one unit of C, we need 0.95k units of L; if we sell one unit of C, we will get 1.1k units of L.
Let us keep this in mind and then build on this.

From statements 3 and 4,
Amounts of L received from sales of B = 88000 × 9595 = 158400.
Number of units of A sold = 88000110K88000110𝐾 = 800K800𝐾.
Number of units of B sold = 158400132K158400132𝐾 = 1200K1200𝐾.
The number of units of B is unchanged. What does this say?
Number of units of B bought = 1200K1200𝐾.
Number of L used to buy this B = 1200K1200𝐾 × 114K = 136800.
The amounts of L used by the outlet to buy A and B are in the ratio 5:3.
Or, the amount of L used to buy A = 136800 × 5353 = 228000.
Number of units of A bought = 22800095K22800095𝐾 = 2400K2400𝐾.
Number of units of A sold = 800K800𝐾. What is the value of K?
Number of units of A added = 1600K1600𝐾. This is equal to 800 or, K = 2. The base exchange
rates are 200, 240 and 2.
Or,
To buy one unit of A, we need 190 units of L; if we sell one unit of A, we will get 220 units of L.
To buy one unit of B, we need 228 units of L; if we sell one unit of B, we will get 264 units of L.
To buy one unit of C, we need 1.9 units of L; if we sell one unit of C, we will get 2.2k units of L.
Now, let us think about currency C.
The amount of L used by the outlet to buy C equals the amount of L it received by selling C.
We also know that we add 3000 units of C during the day.
If the number of units of L for transacting with C were to be called X. We would
buy L1.9𝐿1.9 units of C and sell L2.2𝐿2.2 units of C.
We would add L1.9𝐿1.9 - L2.2𝐿2.2 units of C during the day.
Or, we know that L1.9𝐿1.9 - L2.2𝐿2.2 = 3000.
2.2L−1.9L1.9×2.22.2𝐿−1.9𝐿1.9×2.2 = 3000 or, L = 1000 × 1.9 × 2.2 = 41800.
Now, let us recap whatever we have thus far.

Currency A: We spend 228000 units of L to buy 1200 units of A, we receive 88000 units of L by
selling 400 units of A. We add a total of 800 units of A.
Currency B: We spend 136800 units of L to buy 600 units of B, we receive 158400 units of L by
selling 600 units of B. We add 0 units of B.
Currency C: We spend 41800 units of L to buy 22000 units of C, we receive 41800 units of L by
selling 19000 units of C. We add 3000 units of C.
Let us move on to the questions.
From the inferences, the buying exchange rate of currency C with respect to currency L is 1.9 on
that day.

43.

How many units of currency C did the outlet sell on that day?

A.
3000
B.
22000
C.
6000
D.
19000

Option D is the correct answer.

Video Explanation

Explanatory Answer

In currency transactions, getting the basic outline is very important.
So, if the base rate of A w.r.t to L is 100, then to buy one unit of A, we need 95 units of L and if we
sell one unit of A, we will get 110 units of L.
Let us say the base rate of A w.r.t to L is 100k, then the base rate of B w.r.t to L is 120k and that of
C is 1k.
To buy one unit of A, we need 95k units of L; if we sell one unit of A, we will get 110k units of L.
To buy one unit of B, we need 114k units of L; if we sell one unit of B, we will get 132k units of L.
To buy one unit of C, we need 0.95k units of L; if we sell one unit of C, we will get 1.1k units of L.
Let us keep this in mind and then build on this.
From statements 3 and 4,
Amounts of L received from sales of B = 88000 × 9595 = 158400.
Number of units of A sold = 88000110K88000110𝐾 = 800K800𝐾.
Number of units of B sold = 158400132K158400132𝐾 = 1200K1200𝐾.
The number of units of B is unchanged. What does this say?

Number of units of B bought = 1200K1200𝐾.
Number of L used to buy this B = 1200K1200𝐾 × 114K = 136800.
The amounts of L used by the outlet to buy A and B are in the ratio 5:3.
Or, the amount of L used to buy A = 136800 × 5353 = 228000.
Number of units of A bought = 22800095K22800095𝐾 = 2400K2400𝐾.
Number of units of A sold = 800K800𝐾. What is the value of K?
Number of units of A added = 1600K1600𝐾. This is equal to 800 or, k = 2. The base exchange
rates are 200, 240 and 2.
Or,
To buy one unit of A, we need 190 units of L; if we sell one unit of A, we will get 220 units of L.
To buy one unit of B, we need 228 units of L; if we sell one unit of B, we will get 264 units of L.
To buy one unit of C, we need 1.9 units of L; if we sell one unit of C, we will get 2.2k units of L.
Now, let us think about currency C.
The amount of L used by the outlet to buy C equals the amount of L it received by selling C.
We also know that we add 3000 units of C during the day.
If the number of units of L for transacting with C were to be called X. We would
buy L1.9𝐿1.9 units of C and sell L2.2𝐿2.2 units of C.
We would add L1.9𝐿1.9 - L2.2𝐿2.2 units of C during the day.
Or, we know that L1.9𝐿1.9 - L2.2𝐿2.2 = 3000.
2.2L−1.9L1.9×2.22.2𝐿−1.9𝐿1.9×2.2 = 3000 or, L = 1000 × 1.9 × 2.2 = 41800.
Now, let us recap whatever we have thus far.

Currency A: We spend 228000 units of L to buy 1200 units of A, we receive 88000 units of L by
selling 400 units of A. We add a total of 800 units of A.
Currency B: We spend 136800 units of L to buy 600 units of B, we receive 158400 units of L by
selling 600 units of B. We add 0 units of B.
Currency C: We spend 41800 units of L to buy 22000 units of C, we receive 41800 units of L by
selling 19000 units of C. We add 3000 units of C.
Let us move on to the questions.
From the inferences, we can say that the outlet sells 19000 units of currency C on that day.

44.

What was the base exchange rate of currency B with respect to currency L on that day? [TITA]

Answer : 240

Video Explanation

Explanatory Answer

In currency transactions, getting the basic outline is very important.
So, if the base rate of A w.r.t to L is 100, then to buy one unit of A, we need 95 units of L and if we
sell one unit of A, we will get 110 units of L.
Let us say the base rate of A w.r.t to L is 100k, then the base rate of B w.r.t to L is 120k and that of
C is 1k.
To buy one unit of A, we need 95k units of L; if we sell one unit of A, we will get 110k units of L.
To buy one unit of B, we need 114k units of L; if we sell one unit of B, we will get 132k units of L.
To buy one unit of C, we need 0.95k units of L; if we sell one unit of C, we will get 1.1k units of L.
Let us keep this in mind and then build on this.
From statements 3 and 4,
Amounts of L received from sales of B = 88000 × 9595 = 158400.
Number of units of A sold = 88000110K88000110𝐾 = 800K800𝐾.
Number of units of B sold = 158400132K158400132𝐾 = 1200K1200𝐾.
The number of units of B is unchanged. What does this say?
Number of units of B bought = 1200K1200𝐾.
Number of L used to buy this B = 1200K1200𝐾 × 114K = 136800.
The amounts of L used by the outlet to buy A and B are in the ratio 5:3.
Or, the amount of L used to buy A = 136800 × 5353 = 228000.
Number of units of A bought = 22800095K22800095𝐾 = 2400K2400𝐾.
Number of units of A sold = 800K800𝐾. What is the value of K?
Number of units of A added = 1600K1600𝐾. This is equal to 800 or, K = 2. The base exchange
rates are 200, 240 and 2.
Or,
To buy one unit of A, we need 190 units of L; if we sell one unit of A, we will get 220 units of L.
To buy one unit of B, we need 228 units of L; if we sell one unit of B, we will get 264 units of L.
To buy one unit of C, we need 1.9 units of L; if we sell one unit of C, we will get 2.2k units of L.
Now, let us think about currency C.
The amount of L used by the outlet to buy C equals the amount of L it received by selling C.
We also know that we add 3000 units of C during the day.
If the number of units of L for transacting with C were to be called X. We would
buy L1.9𝐿1.9 units of C and sell L2.2𝐿2.2 units of C.
We would add L1.9𝐿1.9 - L2.2𝐿2.2 units of C during the day.
Or, we know that L1.9𝐿1.9 - L2.2𝐿2.2 = 3000.
2.2L−1.9L1.9×2.22.2𝐿−1.9𝐿1.9×2.2 = 3000 or, L = 1000 × 1.9 × 2.2 = 41800.
Now, let us recap whatever we have thus far.

Currency A: We spend 228000 units of L to buy 1200 units of A, we receive 88000 units of L by
selling 400 units of A. We add a total of 800 units of A.
Currency B: We spend 136800 units of L to buy 600 units of B, we receive 158400 units of L by
selling 600 units of B. We add 0 units of B.
Currency C: We spend 41800 units of L to buy 22000 units of C, we receive 41800 units of L by
selling 19000 units of C. We add 3000 units of C.
Let us move on to the questions.
From the inferences, the base exchange rate of currency B with respect to currency L on that day
is 240

45.

How many units of currency A did the outlet buy on that day? [TITA]

Answer : 1200

Video Explanation

Explanatory Answer

In currency transactions, getting the basic outline is very important.
So, if the base rate of A w.r.t to L is 100, then to buy one unit of A, we need 95 units of L and if we
sell one unit of A, we will get 110 units of L.
Let us say the base rate of A w.r.t to L is 100k, then the base rate of B w.r.t to L is 120k and that of
C is 1k.
To buy one unit of A, we need 95k units of L; if we sell one unit of A, we will get 110k units of L.
To buy one unit of B, we need 114k units of L; if we sell one unit of B, we will get 132k units of L.
To buy one unit of C, we need 0.95k units of L; if we sell one unit of C, we will get 1.1k units of L.
Let us keep this in mind and then build on this.
From statements 3 and 4,
Amounts of L received from sales of B = 88000 × 9595 = 158400.
Number of units of A sold = 88000110K88000110𝐾 = 800K800𝐾.
Number of units of B sold = 158400132K158400132𝐾 = 1200K1200𝐾.
The number of units of B is unchanged. What does this say?
Number of units of B bought = 1200K1200𝐾.
Number of L used to buy this B = 1200K1200𝐾 × 114K = 136800.
The amounts of L used by the outlet to buy A and B are in the ratio 5:3.
Or, the amount of L used to buy A = 136800 × 5353 = 228000.
Number of units of A bought = 22800095K22800095𝐾 = 2400K2400𝐾.
Number of units of A sold = 800K800𝐾. What is the value of K?
Number of units of A added = 1600K1600𝐾. This is equal to 800 or, k = 2. The base exchange
rates are 200, 240 and 2.
Or,
To buy one unit of A, we need 190 units of L; if we sell one unit of A, we will get 220 units of L.
To buy one unit of B, we need 228 units of L; if we sell one unit of B, we will get 264 units of L.
To buy one unit of C, we need 1.9 units of L; if we sell one unit of C, we will get 2.2k units of L.
Now, let us think about currency C.
The amount of L used by the outlet to buy C equals the amount of L it received by selling C.
We also know that we add 3000 units of C during the day.
If the number of units of L for transacting with C were to be called X. We would
buy L1.9𝐿1.9 units of C and sell L2.2𝐿2.2 units of C.
We would add L1.9𝐿1.9 - L2.2𝐿2.2 units of C during the day.
Or, we know that L1.9𝐿1.9 - L2.2𝐿2.2 = 3000.
2.2L−1.9L1.9×2.22.2𝐿−1.9𝐿1.9×2.2 = 3000 or, L = 1000 × 1.9 × 2.2 = 41800.
Now, let us recap whatever we have thus far.

Currency A: We spend 228000 units of L to buy 1200 units of A, we receive 88000 units of L by
selling 400 units of A. We add a total of 800 units of A.
Currency B: We spend 136800 units of L to buy 600 units of B, we receive 158400 units of L by
selling 600 units of B. We add 0 units of B.
Currency C: We spend 41800 units of L to buy 22000 units of C, we receive 41800 units of L by
selling 19000 units of C. We add 3000 units of C.
Let us move on to the questions.
From the inferences, we can say that the outlet buys 1200 units of currency A on that day.

46.

Currency Exchange

The base exchange rate of a currency X with respect to a currency Y is the number of units of currency Y which is equivalent in value to one unit of currency X. Currency exchange outlets buy currency at buying exchange rates that are lower than base exchange rates, and sell currency at selling exchange rates that are higher than base exchange rates.

A currency exchange outlet uses the local currency L to buy and sell three international currencies A, B, and C, but does not exchange one international currency directly with another. The base exchange rates of A, B and C with respect to L are in the ratio 100:120:1. The buying exchange rates of each of A, B, and C with respect to L are 5% below the corresponding base exchange rates, and their selling exchange rates are 10% above their corresponding base exchange rates.

The following facts are known about the outlet on a particular day:
1. The amount of L used by the outlet to buy C equals the amount of L it received by selling C.
2. The amounts of L used by the outlet to buy A and B are in the ratio 5:3.
3. The amounts of L the outlet received from the sales of A and B are in the ratio 5:9.
4. The outlet received 88000 units of L by selling A during the day.
5. The outlet started the day with some amount of L, 2500 units of A, 4800 units of B, and 48000 units of C.
6. The outlet ended the day with some amount of L, 3300 units of A, 4800 units of B,and 51000 units of C.

01.

How many units of currency A did the outlet buy on that day? [TITA]

Answer : 1200

Video Explanation

Explanatory Answer

In currency transactions, getting the basic outline is very important.
So, if the base rate of A w.r.t to L is 100, then to buy one unit of A, we need 95 units of L and if we
sell one unit of A, we will get 110 units of L.
Let us say the base rate of A w.r.t to L is 100k, then the base rate of B w.r.t to L is 120k and that of
C is 1k.
To buy one unit of A, we need 95k units of L; if we sell one unit of A, we will get 110k units of L.
To buy one unit of B, we need 114k units of L; if we sell one unit of B, we will get 132k units of L.
To buy one unit of C, we need 0.95k units of L; if we sell one unit of C, we will get 1.1k units of L.
Let us keep this in mind and then build on this.
From statements 3 and 4,
Amounts of L received from sales of B = 88000 × 9595 = 158400.
Number of units of A sold = 88000110K88000110𝐾 = 800K800𝐾.
Number of units of B sold = 158400132K158400132𝐾 = 1200K1200𝐾.
The number of units of B is unchanged. What does this say?
Number of units of B bought = 1200K1200𝐾.
Number of L used to buy this B = 1200K1200𝐾 × 114K = 136800.
The amounts of L used by the outlet to buy A and B are in the ratio 5:3.
Or, the amount of L used to buy A = 136800 × 5353 = 228000.
Number of units of A bought = 22800095K22800095𝐾 = 2400K2400𝐾.
Number of units of A sold = 800K800𝐾. What is the value of K?
Number of units of A added = 1600K1600𝐾. This is equal to 800 or, k = 2. The base exchange
rates are 200, 240 and 2.
Or,
To buy one unit of A, we need 190 units of L; if we sell one unit of A, we will get 220 units of L.
To buy one unit of B, we need 228 units of L; if we sell one unit of B, we will get 264 units of L.
To buy one unit of C, we need 1.9 units of L; if we sell one unit of C, we will get 2.2k units of L.
Now, let us think about currency C.
The amount of L used by the outlet to buy C equals the amount of L it received by selling C.
We also know that we add 3000 units of C during the day.
If the number of units of L for transacting with C were to be called X. We would
buy L1.9𝐿1.9 units of C and sell L2.2𝐿2.2 units of C.
We would add L1.9𝐿1.9 - L2.2𝐿2.2 units of C during the day.
Or, we know that L1.9𝐿1.9 - L2.2𝐿2.2 = 3000.
2.2L−1.9L1.9×2.22.2𝐿−1.9𝐿1.9×2.2 = 3000 or, L = 1000 × 1.9 × 2.2 = 41800.
Now, let us recap whatever we have thus far.

Currency A: We spend 228000 units of L to buy 1200 units of A, we receive 88000 units of L by
selling 400 units of A. We add a total of 800 units of A.
Currency B: We spend 136800 units of L to buy 600 units of B, we receive 158400 units of L by
selling 600 units of B. We add 0 units of B.
Currency C: We spend 41800 units of L to buy 22000 units of C, we receive 41800 units of L by
selling 19000 units of C. We add 3000 units of C.
Let us move on to the questions.
From the inferences, we can say that the outlet buys 1200 units of currency A on that day.

02.

How many units of currency C did the outlet sell on that day?

A.
3000
B.
22000
C.
6000
D.
19000

Option D is the correct answer.

Video Explanation

Explanatory Answer

In currency transactions, getting the basic outline is very important.
So, if the base rate of A w.r.t to L is 100, then to buy one unit of A, we need 95 units of L and if we
sell one unit of A, we will get 110 units of L.
Let us say the base rate of A w.r.t to L is 100k, then the base rate of B w.r.t to L is 120k and that of
C is 1k.
To buy one unit of A, we need 95k units of L; if we sell one unit of A, we will get 110k units of L.
To buy one unit of B, we need 114k units of L; if we sell one unit of B, we will get 132k units of L.
To buy one unit of C, we need 0.95k units of L; if we sell one unit of C, we will get 1.1k units of L.
Let us keep this in mind and then build on this.
From statements 3 and 4,
Amounts of L received from sales of B = 88000 × 9595 = 158400.
Number of units of A sold = 88000110K88000110𝐾 = 800K800𝐾.
Number of units of B sold = 158400132K158400132𝐾 = 1200K1200𝐾.
The number of units of B is unchanged. What does this say?

Number of units of B bought = 1200K1200𝐾.
Number of L used to buy this B = 1200K1200𝐾 × 114K = 136800.
The amounts of L used by the outlet to buy A and B are in the ratio 5:3.
Or, the amount of L used to buy A = 136800 × 5353 = 228000.
Number of units of A bought = 22800095K22800095𝐾 = 2400K2400𝐾.
Number of units of A sold = 800K800𝐾. What is the value of K?
Number of units of A added = 1600K1600𝐾. This is equal to 800 or, k = 2. The base exchange
rates are 200, 240 and 2.
Or,
To buy one unit of A, we need 190 units of L; if we sell one unit of A, we will get 220 units of L.
To buy one unit of B, we need 228 units of L; if we sell one unit of B, we will get 264 units of L.
To buy one unit of C, we need 1.9 units of L; if we sell one unit of C, we will get 2.2k units of L.
Now, let us think about currency C.
The amount of L used by the outlet to buy C equals the amount of L it received by selling C.
We also know that we add 3000 units of C during the day.
If the number of units of L for transacting with C were to be called X. We would
buy L1.9𝐿1.9 units of C and sell L2.2𝐿2.2 units of C.
We would add L1.9𝐿1.9 - L2.2𝐿2.2 units of C during the day.
Or, we know that L1.9𝐿1.9 - L2.2𝐿2.2 = 3000.
2.2L−1.9L1.9×2.22.2𝐿−1.9𝐿1.9×2.2 = 3000 or, L = 1000 × 1.9 × 2.2 = 41800.
Now, let us recap whatever we have thus far.

Currency A: We spend 228000 units of L to buy 1200 units of A, we receive 88000 units of L by
selling 400 units of A. We add a total of 800 units of A.
Currency B: We spend 136800 units of L to buy 600 units of B, we receive 158400 units of L by
selling 600 units of B. We add 0 units of B.
Currency C: We spend 41800 units of L to buy 22000 units of C, we receive 41800 units of L by
selling 19000 units of C. We add 3000 units of C.
Let us move on to the questions.
From the inferences, we can say that the outlet sells 19000 units of currency C on that day.

03.

What was the base exchange rate of currency B with respect to currency L on that day? [TITA]

Answer : 240

Video Explanation

Explanatory Answer

In currency transactions, getting the basic outline is very important.
So, if the base rate of A w.r.t to L is 100, then to buy one unit of A, we need 95 units of L and if we
sell one unit of A, we will get 110 units of L.
Let us say the base rate of A w.r.t to L is 100k, then the base rate of B w.r.t to L is 120k and that of
C is 1k.
To buy one unit of A, we need 95k units of L; if we sell one unit of A, we will get 110k units of L.
To buy one unit of B, we need 114k units of L; if we sell one unit of B, we will get 132k units of L.
To buy one unit of C, we need 0.95k units of L; if we sell one unit of C, we will get 1.1k units of L.
Let us keep this in mind and then build on this.
From statements 3 and 4,
Amounts of L received from sales of B = 88000 × 9595 = 158400.
Number of units of A sold = 88000110K88000110𝐾 = 800K800𝐾.
Number of units of B sold = 158400132K158400132𝐾 = 1200K1200𝐾.
The number of units of B is unchanged. What does this say?
Number of units of B bought = 1200K1200𝐾.
Number of L used to buy this B = 1200K1200𝐾 × 114K = 136800.
The amounts of L used by the outlet to buy A and B are in the ratio 5:3.
Or, the amount of L used to buy A = 136800 × 5353 = 228000.
Number of units of A bought = 22800095K22800095𝐾 = 2400K2400𝐾.
Number of units of A sold = 800K800𝐾. What is the value of K?
Number of units of A added = 1600K1600𝐾. This is equal to 800 or, K = 2. The base exchange
rates are 200, 240 and 2.
Or,
To buy one unit of A, we need 190 units of L; if we sell one unit of A, we will get 220 units of L.
To buy one unit of B, we need 228 units of L; if we sell one unit of B, we will get 264 units of L.
To buy one unit of C, we need 1.9 units of L; if we sell one unit of C, we will get 2.2k units of L.
Now, let us think about currency C.
The amount of L used by the outlet to buy C equals the amount of L it received by selling C.
We also know that we add 3000 units of C during the day.
If the number of units of L for transacting with C were to be called X. We would
buy L1.9𝐿1.9 units of C and sell L2.2𝐿2.2 units of C.
We would add L1.9𝐿1.9 - L2.2𝐿2.2 units of C during the day.
Or, we know that L1.9𝐿1.9 - L2.2𝐿2.2 = 3000.
2.2L−1.9L1.9×2.22.2𝐿−1.9𝐿1.9×2.2 = 3000 or, L = 1000 × 1.9 × 2.2 = 41800.
Now, let us recap whatever we have thus far.

Currency A: We spend 228000 units of L to buy 1200 units of A, we receive 88000 units of L by
selling 400 units of A. We add a total of 800 units of A.
Currency B: We spend 136800 units of L to buy 600 units of B, we receive 158400 units of L by
selling 600 units of B. We add 0 units of B.
Currency C: We spend 41800 units of L to buy 22000 units of C, we receive 41800 units of L by
selling 19000 units of C. We add 3000 units of C.
Let us move on to the questions.
From the inferences, the base exchange rate of currency B with respect to currency L on that day
is 240

04.

What was the buying exchange rate of currency C with respect to currency L on that day?

A.
1.10
B.
0.95
C.
2.20
D.
1.90

Option D is the correct answer.

Video Explanation

Explanatory Answer

In currency transactions, getting the basic outline is very important.
So, if the base rate of A w.r.t to L is 100, then to buy one unit of A, we need 95 units of L and if we
sell one unit of A, we will get 110 units of L.
Let us say the base rate of A w.r.t to L is 100k, then the base rate of B w.r.t to L is 120k and that of
C is 1k.
To buy one unit of A, we need 95k units of L; if we sell one unit of A, we will get 110k units of L.
To buy one unit of B, we need 114k units of L; if we sell one unit of B, we will get 132k units of L.
To buy one unit of C, we need 0.95k units of L; if we sell one unit of C, we will get 1.1k units of L.
Let us keep this in mind and then build on this.

From statements 3 and 4,
Amounts of L received from sales of B = 88000 × 9595 = 158400.
Number of units of A sold = 88000110K88000110𝐾 = 800K800𝐾.
Number of units of B sold = 158400132K158400132𝐾 = 1200K1200𝐾.
The number of units of B is unchanged. What does this say?
Number of units of B bought = 1200K1200𝐾.
Number of L used to buy this B = 1200K1200𝐾 × 114K = 136800.
The amounts of L used by the outlet to buy A and B are in the ratio 5:3.
Or, the amount of L used to buy A = 136800 × 5353 = 228000.
Number of units of A bought = 22800095K22800095𝐾 = 2400K2400𝐾.
Number of units of A sold = 800K800𝐾. What is the value of K?
Number of units of A added = 1600K1600𝐾. This is equal to 800 or, K = 2. The base exchange
rates are 200, 240 and 2.
Or,
To buy one unit of A, we need 190 units of L; if we sell one unit of A, we will get 220 units of L.
To buy one unit of B, we need 228 units of L; if we sell one unit of B, we will get 264 units of L.
To buy one unit of C, we need 1.9 units of L; if we sell one unit of C, we will get 2.2k units of L.
Now, let us think about currency C.
The amount of L used by the outlet to buy C equals the amount of L it received by selling C.
We also know that we add 3000 units of C during the day.
If the number of units of L for transacting with C were to be called X. We would
buy L1.9𝐿1.9 units of C and sell L2.2𝐿2.2 units of C.
We would add L1.9𝐿1.9 - L2.2𝐿2.2 units of C during the day.
Or, we know that L1.9𝐿1.9 - L2.2𝐿2.2 = 3000.
2.2L−1.9L1.9×2.22.2𝐿−1.9𝐿1.9×2.2 = 3000 or, L = 1000 × 1.9 × 2.2 = 41800.
Now, let us recap whatever we have thus far.

Currency A: We spend 228000 units of L to buy 1200 units of A, we receive 88000 units of L by
selling 400 units of A. We add a total of 800 units of A.
Currency B: We spend 136800 units of L to buy 600 units of B, we receive 158400 units of L by
selling 600 units of B. We add 0 units of B.
Currency C: We spend 41800 units of L to buy 22000 units of C, we receive 41800 units of L by
selling 19000 units of C. We add 3000 units of C.
Let us move on to the questions.
From the inferences, the buying exchange rate of currency C with respect to currency L is 1.9 on
that day.

47.

Which set of letters CANNOT be coded with the same digit?

A.
S , U , V
B.
X , Y , Z
C.
S , E , Z
D.

I , B , M

Option A is the correct answer.

Video Explanation

Explanatory Answer

Digits 1 to 8 are mapped to 3 letters each, 9 is mapped to only 2.
(3 × 8) + 2 = 26 which is the total number of letters in English.
Each letter is mapped to a unique code, but remember that each number is mapped
to 2323 letters.
It is best to start from the small words. Let us attack ‘is’ and ‘as’ first.
IS = 35, AS = 56. S = 5 , I = 3 , A = 6.
Now, THE is 458. OF = 79. PEACOCK does not have a ‘7’ in in. It has an O but no F, so F should be
7 and O should be 9.

THE has 458, DESIGNATED has T and E but no H. Is there a number in THE but not in
DESIGNATED?
H should be 4. T and E should be 5 and 8 in some order.
Now let us look at INDIA. INDIA = 13366. I = 3 and A = 6. So, N and D should be 1 and 6 in some
order. BIRD has a D, BIRD = 1334.
What does this mean? This tells us D = 1 and N = 6.
Let us have another look at T and E. T and E and 5 and 8 in some order. Is there a word that has
only one of T & E but not both?
NATIONAL has T but not E. NATIONAL has 8 but not 5. BINGO! We know T has to be 8 and E has
to be 5.
Now let us go word by word. PEACOCK = P56C9CK. So, PCCK should be 8899. 9 is allotted only
to two numbers.
We know that O = 9. So, what can we say about 9?
If C takes 8, then both P and K becomes 9 which is not possible as 9 can be assigned to only two
letters.
Therefore C has to take 9 and P , K takes the value 8.
DESIGNATED = 1553G66851. The missing number should be G. Or, G = 7.
NATIONAL = 6683966L. The missing number should be L. Or, L should be 1.
BIRD = B3R1. 3 and 4 are missing. B and R should be 3 and 4 in some order.
B and R occur only once each in this sequence, so there is no way of resolving this.

Consider option A S , U, V. We know that S takes 5. If both U and V takes 5 then there will be 4
letters coded to 5.
This is not possible.

48.

For how many digits can the complete list of letters associated with that digit be identified?

A.
2
B.
1
C.
0
D.
3

Option A is the correct answer.

Video Explanation

Explanatory Answer

Digits 1 to 8 are mapped to 3 letters each, 9 is mapped to only 2.
(3 × 8) + 2 = 26 which is the total number of letters in English.
Each letter is mapped to a unique code, but remember that each number is mapped
to 2323 letters.
It is best to start from the small words. Let us attack ‘is’ and ‘as’ first.
IS = 35, AS = 56. S = 5 , I = 3 , A = 6.
Now, THE is 458. OF = 79. PEACOCK does not have a ‘7’ in in. It has an O but no F, so F should be
7 and O should be 9.
THE has 458, DESIGNATED has T and E but no H. Is there a number in THE but not in
DESIGNATED?
H should be 4. T and E should be 5 and 8 in some order.
Now let us look at INDIA. INDIA = 13366. I = 3 and A = 6. So, N and D should be 1 and 6 in some
order. BIRD has a D, BIRD = 1334.
What does this mean? This tells us D = 1 and N = 6.
Let us have another look at T and E. T and E and 5 and 8 in some order. Is there a word that has
only one of T & E but not both?

NATIONAL has T but not E. NATIONAL has 8 but not 5. BINGO! We know T has to be 8 and E has
to be 5.
Now let us go word by word. PEACOCK = P56C9CK. So, PCCK should be 8899. 9 is allotted only
to two numbers.
We know that O = 9. So, what can we say about 9?
If C takes 8, then both P and K becomes 9 which is not possible as 9 can be assigned to only two
letters.
Therefore C has to take 9 and P , K takes the value 8.
DESIGNATED = 1553G66851. The missing number should be G. Or, G = 7.
NATIONAL = 6683966L. The missing number should be L. Or, L should be 1.
BIRD = B3R1. 3 and 4 are missing. B and R should be 3 and 4 in some order.
B and R occur only once each in this sequence, so there is no way of resolving this.

From
the above inferences, we can see that only two letters can be associated with digits for sure.

49.

What best can be concluded about the code for the letter L?

A.
6
B.
8
C.
1 or 8
D.
1

Option D is the correct answer.

Video Explanation

Explanatory Answer

Digits 1 to 8 are mapped to 3 letters each, 9 is mapped to only 2.
(3 × 8) + 2 = 26 which is the total number of letters in English.
Each letter is mapped to a unique code, but remember that each number is mapped
to 2323 letters.
It is best to start from the small words. Let us attack ‘is’ and ‘as’ first.
IS = 35, AS = 56. S = 5 , I = 3 , A = 6.
Now, THE is 458. OF = 79. PEACOCK does not have a ‘7’ in in. It has an O but no F, so F should be
7 and O should be 9.
THE has 458, DESIGNATED has T and E but no H. Is there a number in THE but not in
DESIGNATED?
H should be 4. T and E should be 5 and 8 in some order.
Now let us look at INDIA. INDIA = 13366. I = 3 and A = 6. So, N and D should be 1 and 6 in some
order. BIRD has a D, BIRD = 1334.
What does this mean? This tells us D = 1 and N = 6.
Let us have another look at T and E. T and E and 5 and 8 in some order. Is there a word that has
only one of T & E but not both?
NATIONAL has T but not E. NATIONAL has 8 but not 5. BINGO! We know T has to be 8 and E has
to be 5.
Now let us go word by word. PEACOCK = P56C9CK. So, PCCK should be 8899. 9 is allotted only
to two numbers.
We know that O = 9. So, what can we say about 9?
If C takes 8, then both P and K becomes 9 which is not possible as 9 can be assigned to only two
letters.
Therefore C has to take 9 and P , K takes the value 8.
DESIGNATED = 1553G66851. The missing number should be G. Or, G = 7.
NATIONAL = 6683966L. The missing number should be L. Or, L should be 1.
BIRD = B3R1. 3 and 4 are missing. B and R should be 3 and 4 in some order.
B and R occur only once each in this sequence, so there is no way of resolving this.

From the above inferences, we can see that L takes 1.

50.

Letter Codes

According to a coding scheme the sentence,
Peacock is designated as the national bird of India is coded as 5688999 35 1135556678 56 458 13666689 1334 79 13366
This coding scheme has the following rules:
1. The scheme is case-insensitive (does not distinguish between upper case and lower case letters).
2. Each letter has a unique code which is a single digit from among 1,2,3,......,9.
3. The digit 9 codes two letters, and every other digit codes three letters.
4. The code for a word is constructed by arranging the digits corresponding to its letters in a non-decreasing sequence.
Answer these questions on the basis of this information

01.

What best can be concluded about the code for the letter L?

A.
6
B.
8
C.
1 or 8
D.
1

Option D is the correct answer.

Video Explanation

Explanatory Answer

Digits 1 to 8 are mapped to 3 letters each, 9 is mapped to only 2.
(3 × 8) + 2 = 26 which is the total number of letters in English.
Each letter is mapped to a unique code, but remember that each number is mapped
to 2323 letters.
It is best to start from the small words. Let us attack ‘is’ and ‘as’ first.
IS = 35, AS = 56. S = 5 , I = 3 , A = 6.
Now, THE is 458. OF = 79. PEACOCK does not have a ‘7’ in in. It has an O but no F, so F should be
7 and O should be 9.
THE has 458, DESIGNATED has T and E but no H. Is there a number in THE but not in
DESIGNATED?
H should be 4. T and E should be 5 and 8 in some order.
Now let us look at INDIA. INDIA = 13366. I = 3 and A = 6. So, N and D should be 1 and 6 in some
order. BIRD has a D, BIRD = 1334.
What does this mean? This tells us D = 1 and N = 6.
Let us have another look at T and E. T and E and 5 and 8 in some order. Is there a word that has
only one of T & E but not both?
NATIONAL has T but not E. NATIONAL has 8 but not 5. BINGO! We know T has to be 8 and E has
to be 5.
Now let us go word by word. PEACOCK = P56C9CK. So, PCCK should be 8899. 9 is allotted only
to two numbers.
We know that O = 9. So, what can we say about 9?
If C takes 8, then both P and K becomes 9 which is not possible as 9 can be assigned to only two
letters.
Therefore C has to take 9 and P , K takes the value 8.
DESIGNATED = 1553G66851. The missing number should be G. Or, G = 7.
NATIONAL = 6683966L. The missing number should be L. Or, L should be 1.
BIRD = B3R1. 3 and 4 are missing. B and R should be 3 and 4 in some order.
B and R occur only once each in this sequence, so there is no way of resolving this.

From the above inferences, we can see that L takes 1.

02.

What best can be concluded about the code for the letter B?

A.
1 or 3 or 4
B.
1
C.
3
D.

3 or 4

Option D is the correct answer.

Video Explanation

Explanatory Answer

Digits 1 to 8 are mapped to 3 letters each, 9 is mapped to only 2.
(3 × 8) + 2 = 26 which is the total number of letters in English.
Each letter is mapped to a unique code, but remember that each number is mapped
to 2323 letters.
It is best to start from the small words. Let us attack ‘is’ and ‘as’ first.
IS = 35, AS = 56. S = 5 , I = 3 , A = 6.
Now, THE is 458. OF = 79. PEACOCK does not have a ‘7’ in in. It has an O but no F, so F should be
7 and O should be 9.
THE has 458, DESIGNATED has T and E but no H. Is there a number in THE but not in
DESIGNATED?
H should be 4. T and E should be 5 and 8 in some order.
Now let us look at INDIA. INDIA = 13366. I = 3 and A = 6. So, N and D should be 1 and 6 in some
order. BIRD has a D, BIRD = 1334.
What does this mean? This tells us D = 1 and N = 6.
Let us have another look at T and E. T and E and 5 and 8 in some order. Is there a word that has
only one of T & E but not both?
NATIONAL has T but not E. NATIONAL has 8 but not 5. BINGO! We know T has to be 8 and E has
to be 5.
Now let us go word by word. PEACOCK = P56C9CK. So, PCCK should be 8899. 9 is allotted only
to two numbers.
We know that O = 9. So, what can we say about 9?
If C takes 8, then both P and K becomes 9 which is not possible as 9 can be assigned to only two letters.
Therefore C has to take 9 and P , K takes the value 8.
DESIGNATED = 1553G66851. The missing number should be G. Or, G = 7.
NATIONAL = 6683966L. The missing number should be L. Or, L should be 1.
BIRD = B3R1. 3 and 4 are missing. B and R should be 3 and 4 in some order.
B and R occur only once each in this sequence, so there is no way of resolving this.

From the above inferences, we can see that B takes either 3 or 4.

03.

For how many digits can the complete list of letters associated with that digit be identified?

A.
2
B.
1
C.
0
D.
3

Option A is the correct answer.

Video Explanation

Explanatory Answer

Digits 1 to 8 are mapped to 3 letters each, 9 is mapped to only 2.
(3 × 8) + 2 = 26 which is the total number of letters in English.
Each letter is mapped to a unique code, but remember that each number is mapped
to 2323 letters.
It is best to start from the small words. Let us attack ‘is’ and ‘as’ first.
IS = 35, AS = 56. S = 5 , I = 3 , A = 6.
Now, THE is 458. OF = 79. PEACOCK does not have a ‘7’ in in. It has an O but no F, so F should be
7 and O should be 9.
THE has 458, DESIGNATED has T and E but no H. Is there a number in THE but not in
DESIGNATED?
H should be 4. T and E should be 5 and 8 in some order.
Now let us look at INDIA. INDIA = 13366. I = 3 and A = 6. So, N and D should be 1 and 6 in some
order. BIRD has a D, BIRD = 1334.
What does this mean? This tells us D = 1 and N = 6.
Let us have another look at T and E. T and E and 5 and 8 in some order. Is there a word that has
only one of T & E but not both?

NATIONAL has T but not E. NATIONAL has 8 but not 5. BINGO! We know T has to be 8 and E has
to be 5.
Now let us go word by word. PEACOCK = P56C9CK. So, PCCK should be 8899. 9 is allotted only
to two numbers.
We know that O = 9. So, what can we say about 9?
If C takes 8, then both P and K becomes 9 which is not possible as 9 can be assigned to only two
letters.
Therefore C has to take 9 and P , K takes the value 8.
DESIGNATED = 1553G66851. The missing number should be G. Or, G = 7.
NATIONAL = 6683966L. The missing number should be L. Or, L should be 1.
BIRD = B3R1. 3 and 4 are missing. B and R should be 3 and 4 in some order.
B and R occur only once each in this sequence, so there is no way of resolving this.

From
the above inferences, we can see that only two letters can be associated with digits for sure.

04.

Which set of letters CANNOT be coded with the same digit?

A.
S , U , V
B.
X , Y , Z
C.
S , E , Z
D.

I , B , M

Option A is the correct answer.

Video Explanation

Explanatory Answer

Digits 1 to 8 are mapped to 3 letters each, 9 is mapped to only 2.
(3 × 8) + 2 = 26 which is the total number of letters in English.
Each letter is mapped to a unique code, but remember that each number is mapped
to 2323 letters.
It is best to start from the small words. Let us attack ‘is’ and ‘as’ first.
IS = 35, AS = 56. S = 5 , I = 3 , A = 6.
Now, THE is 458. OF = 79. PEACOCK does not have a ‘7’ in in. It has an O but no F, so F should be
7 and O should be 9.

THE has 458, DESIGNATED has T and E but no H. Is there a number in THE but not in
DESIGNATED?
H should be 4. T and E should be 5 and 8 in some order.
Now let us look at INDIA. INDIA = 13366. I = 3 and A = 6. So, N and D should be 1 and 6 in some
order. BIRD has a D, BIRD = 1334.
What does this mean? This tells us D = 1 and N = 6.
Let us have another look at T and E. T and E and 5 and 8 in some order. Is there a word that has
only one of T & E but not both?
NATIONAL has T but not E. NATIONAL has 8 but not 5. BINGO! We know T has to be 8 and E has
to be 5.
Now let us go word by word. PEACOCK = P56C9CK. So, PCCK should be 8899. 9 is allotted only
to two numbers.
We know that O = 9. So, what can we say about 9?
If C takes 8, then both P and K becomes 9 which is not possible as 9 can be assigned to only two
letters.
Therefore C has to take 9 and P , K takes the value 8.
DESIGNATED = 1553G66851. The missing number should be G. Or, G = 7.
NATIONAL = 6683966L. The missing number should be L. Or, L should be 1.
BIRD = B3R1. 3 and 4 are missing. B and R should be 3 and 4 in some order.
B and R occur only once each in this sequence, so there is no way of resolving this.

Consider option A S , U, V. We know that S takes 5. If both U and V takes 5 then there will be 4
letters coded to 5.
This is not possible.

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